MATH 111 Calculus I \(\quad\;\;\) Instructor: Difeng Cai


4.2 The Mean Value Theorem

Review of The Intermediate Value Theorem(IVT)

Remark. IVT does not invovle any derivative!

Rolle’s Theorem

Let \(f\) be a function that satisfies the following three hypotheses:

  1. \(f\) is continuous on the closed interval .
  2. \(f\) is differentiable on the open interval .
  3. \(f(a)=f(b)\)

Then there is a number \(c\) in \((a,b)\) such that \(f'(c)=0\).

Four functions that satisfy the assumptions in Rolles' Theorem:

Example. Check if the assumptions in Rolles theorem are satisfied in the following cases.
(1). \(f(x)= \dfrac{1}{(x-1)^2}\) on \([0,2] \quad \) (2). \(f(x)=|x|\) on \([-1,1]\quad\) (3). \(f(x)=\sin x\) on \([0,\pi]\)

Example. Prove that the equation \(x^3+x-1=0\) has exactly one real root.

The Mean Value Theorem

Example 1. Find all numbers \(c\) that satisfy the conclusion of MVT for \(f(x)=3x^2-x+2\) on \([0,3]\).
Sol: \[f'(c)=\dfrac{f(3)-f(0)}{3-0}\text{ for some } c\in (0,3)\] That is, \[6c-1=\dfrac{26-2}{3}=8\] So \(c=\dfrac{3}{2}\) and \(c\) is indeed in \((0,3)\).

Example 2. Find all numbers \(c\) that satisfy the conclusion of MVT for \(f(x)=x^3-x\) on \([0,2]\).
Sol: \[f'(c)=\dfrac{f(2)-f(0)}{2-0}\text{ for some } c\in (0,2)\] That is, \[3c^2-1=\dfrac{6-0}{2}=3\] So \(c^2=\dfrac{4}{3}\), \(c=\pm \sqrt{\dfrac{4}{3}}\). Recall that \(c\) should be in \((0,2)\), so \(c=\sqrt{\dfrac{4}{3}}\).

Example 3.